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django报错解决:view must be a callable or a list/tuple in the case of include().

django版本:1.11.15

django应用,修改urls.py后,访问报错:
TypeError at /
view must be a callable or a list/tuple in the case of include().

修改后的urls.py文件:

from django.conf.urls import url
from django.contrib import admin

urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^$', 'hello.views.home',name='home'),
url(r'^hello/$', 'hello.views.hello',name='hello'),
]

这是因为:从1.10后django后patterns被移除了,已经没有这个模块了。

修改为:

from django.conf.urls import url
from django.contrib import admin
from hello import views

urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^$', views.home,name='home'),
url(r'^hello/$', views.hello,name='hello'),
]

重启uwsgi后,访问正常。

其实urls.py里已经注释说明了:

"""hello URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
https://docs.djangoproject.com/en/1.11/topics/http/urls/
Examples:
Function views
1. Add an import: from my_app import views
2. Add a URL to urlpatterns: url(r'^$', views.home, name='home')
Class-based views
1. Add an import: from other_app.views import Home
2. Add a URL to urlpatterns: url(r'^$', Home.as_view(), name='home')
Including another URLconf
1. Import the include() function: from django.conf.urls import url, include
2. Add a URL to urlpatterns: url(r'^blog/', include('blog.urls'))
"""

django版本差异造成的,o(╥﹏╥)o

done!

作者:zqifa

出处:https://www.l1mn.com

原文地址:https://www.l1mn.com/p/fbzrw4.html

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分类:django
标签:django

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